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Home/ Questions/Q 5938733
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:43:39+00:00 2026-05-22T15:43:39+00:00

I have a table in MySQL with this format: (time = timestamp on insert)

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I have a table in MySQL with this format: (time = timestamp on insert)

id |    tid |   uid |   time
31 |    1   |   14  |   2011-05-19 05:42:37   //start timestamp)
41 |    1   |   14  |   2011-05-19 07:18:42   //stop timestamp)
45 |    1   |   14  |   2011-05-19 07:18:49   //start timestamp)
46 |    1   |   14  |   2011-05-19 07:28:42   //stop timestamp)

What I need is to make a select that adds the time differences like this

(41 - 31) + (46 - 45) (i’m using the id’s instead of the actual time values to better understand what I need to do )

something like SELECT (something that does this) AS TotalTimeSpent WHERE tid = '1'

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:43:39+00:00Added an answer on May 22, 2026 at 3:43 pm

    If you insist on using this table layout (and I really hope you change your mind, it is truly horrific), you can do it with cursors in a stored procedure.

    Pseudo-code would be something like this:

    CREATE PROCEDURE gettotaltime()
    BEGIN
      DECLARE total, curr, prev DATETIME;
      DECLARE odd INT DEFAULT 1;
      DECLARE done INT DEFAULT 0;
    
      DECLARE c CURSOR FOR SELECT time FROM tbl;
      DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
      OPEN c;
    
      read_loop: LOOP
        FETCH c INTO curr;
    
        IF odd=0 THEN 
          SET total=dateadd(total,datediff(curr,prev));   -- or something similar, I forget
        END IF;
    
        SET prev=curr;
        SET odd=1-odd;
    
        IF done THEN
          LEAVE read_loop;
        END IF;
      END LOOP;
    
      CLOSE c;
    
      SELECT total;
    END;
    
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