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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:42:56+00:00 2026-05-14T07:42:56+00:00

I have a table in SQL database: ID Data Value 1 1 0.1 1

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I have a table in SQL database:

ID  Data  Value
1    1     0.1
1    2     0.4
2    10    0.3
2    11    0.2
3    10    0.5
3    11    0.6

For each unique value in Data, I want to filter out the row with the largest ID. For example: In the table above, I want to filter out the third and fourth row because the fifth and sixth rows have the same Data values but their IDs (3) are larger (2 in the third and fourth row).

I tried this in Linq to Entities:

IQueryable<DerivedRate> test = ObjectContext.DerivedRates.OrderBy(d => d.Data).ThenBy(d => d.ID).SkipWhile((d, index) => (index == size - 1) || (d.ID != ObjectContext.DerivedRates.ElementAt(index + 1).ID));

Basically, I am sorting the list and removing the duplicates by checking if the next element has an identical ID.

However, this doesn’t work because SkipWhile(index) and ElementAt(index) aren’t supported in Linq to Entities. I don’t want to pull the entire gigantic table into an array before sorting it. Is there a way?

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:42:57+00:00Added an answer on May 14, 2026 at 7:42 am

    You can use the GroupBy and Max function for that.

    IQueryable<DerivedRate> test = (from d in ObjectContext.DerivedRates
                                 let grouped = ObjectContext.DerivedRates.GroupBy(dr => dr.Data).First()
                                 where d.Data == grouped.Key && d.ID == grouped.Max(dg => dg.ID)
                                 orderby d.Data
                                 select d);
    
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