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Home/ Questions/Q 3390886
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T03:44:35+00:00 2026-05-18T03:44:35+00:00

I have a table in SQL Server 2000 with a text field containing XML

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I have a table in SQL Server 2000 with a text field containing XML that I need to display on a C# ASP.NET 2.0 page. I need to retrieve the XML and then filter out a list of about 80 possible elements (or white list 20 possible elements to keep might be better).

I can pull the xml out of the DB and display it on my .aspx page, but I am not sure how to filter out any elements first.

Example XML

<Message> 
  <MessageNumber>
    1234
  </MessageNumber> 
  <MessageType>
    Auto Notice
  </MessageType> 
  <UPMessageNumber>
    5501
  </UPMessageNumber> 
  <MessageID>
    121223
  </MessageID> 
  <ResponseTo>
    654321
  </ResponseTo>
  <DateTime>
    2010-11-10 09:35:00
  </DateTime>
</Message> 

In this case I will need to filter out the UPMessageNumber and MessageID before displaying it on the page.

Thanks for any ideas.

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  1. Editorial Team
    Editorial Team
    2026-05-18T03:44:35+00:00Added an answer on May 18, 2026 at 3:44 am

    You can do this using XSLT to transform input XML into a modified output.

    C# example here.

    This step-by-step article shows you
    how to apply an Extensible Stylesheet
    Language (XSL) Transformation (XSLT)
    to an Extensible Markup Language (XML)
    document by using the XslTransform
    class to create a new XML document.
    XSL is an XML-based language that is
    designed to transform one XML document
    into another XML document or an XML
    document into any other structured
    document.

    The previous question here addresses directly how to construct XSL for element stripping.

    I think the XSL you need is:

    <?xml version="1.0"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
      <xsl:output method="xml"/>
    
      <xsl:template match="@*|node()" priority="10">
        <xsl:copy>
          <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
      </xsl:template>
    
      <xsl:template match="UPMessageNumber | MessageID" priority="20">
      </xsl:template>
    
    </xsl:stylesheet>
    

    The first xsl:template copies all nodes by default. The second omits the named elements.

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