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Home/ Questions/Q 8218479
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Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T12:48:30+00:00 2026-06-07T12:48:30+00:00

I have a table like the following ————————- | aid | tid | dft

  • 0

I have a table like the following

-------------------------
|  aid  |  tid  |  dft  |
-------------------------
|   1   |   1   |   Y   |
-------------------------
|   1   |   2   |   N   |
-------------------------
|   2   |   3   |   Y   |
-------------------------
|   3   |   4   |   Y   |
-------------------------
|   3   |   5   |   N   |
-------------------------

I want to query the table to get the tid out based on aid and tid but if the tid does not exist for that aid then it should return the default tid (identified by Y in the dft column).

I have tried the following which does not throw an error but returns NULL

SELECT

IF (
    t1.tid IS NOT NULL,
    t1.tid,
    (
        SELECT
            t2.tid
        FROM
            table t2
        WHERE
            t2.aid = 1
        AND t2.dft = 'Y'
    )
) AS tid
FROM
    table t1
WHERE
    t1.aid = 1
AND t1.tid = 3

As that code is looking up tid 3 with aid 1 that doesn’t exist so should return tid of 1 as that is what is marked as Y in the dft column.

Can anybody help?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T12:48:33+00:00Added an answer on June 7, 2026 at 12:48 pm

    Try this:

    SELECT tid
     FROM table t1
    WHERE t1.aid = 1
      AND t1.tid = 3
    UNION   
    SELECT tid
     FROM table t1
    WHERE t1.aid = 1
      AND t1.tid <> 3
      AND dft = 'Y'
    

    If the combination of aid and tid is unique then you can use this version:

    SELECT tid
     FROM table t1
    WHERE t1.aid = 1
      AND (t1.tid = 3 OR dft = 'Y')
    ORDER BY dft LIMIT 1
    
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