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Asked: 2026-05-26T02:32:10+00:00

I have a table like the following : ID |INFO | DATE_DT ————————- 1091|info5

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I have a table like the following : 

ID  |INFO     | DATE_DT
-------------------------
1091|info5    |10/10/2010
1239|old.info |14/09/2010
1340|old.info |07/10/2010
3481|info     |16/10/2010
4134|info3    |21/01/2011

i would like to display just one row with the following conditions :
– if i have in my table one row with INFO = 'info' –> display just this row
– if i dont have one row with INFO = 'info' so i –> display the row with INFO = 'old.info' and DATE_DT = MAX(DATE_DT)

so, in my example if my table is :

ID  |INFO     | DATE_DT
-------------------------
1091|info5    |10/10/2010
1239|old.info |14/09/2010
1340|old.info |07/10/2010
3481|info     |16/10/2010 ===> display this row
4134|info3    |21/01/2011

or if my table doesnt containt INFO = ‘info’

ID  |INFO     | DATE_DT
-------------------------
1091|info5    |10/10/2010
1239|old.info |14/09/2010
1340|old.info |07/10/2010 ===> display this row
4134|info3    |21/01/2011

any suggestions?

Thanks.

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1 Answer

  1. Editorial Team

    You could select both row and take by priority the one that satisfies the first condition:

    SQL> WITH my_table AS (
  2  SELECT 1091 id, 'info5' info, to_date('10/10/2010') date_dt FROM DUAL
  3  UNION ALL SELECT 1239, 'old.info' , to_date('14/09/2010') FROM DUAL
  4  UNION ALL SELECT 1340, 'old.info' , to_date('07/10/2010') FROM DUAL
  5  UNION ALL SELECT 3481, 'info'     , to_date('16/10/2010') FROM DUAL
  6  UNION ALL SELECT 4134, 'info3'    , to_date('21/01/2011') FROM DUAL)
  7  SELECT * FROM (
  8     SELECT 1 ord, t.*
  9       FROM my_table t
 10      WHERE info = 'info'
 11     UNION ALL
 12     SELECT 2 ord, t.*
 13       FROM my_table t
 14      WHERE date_dt = (SELECT MAX(date_dt) FROM my_table)
 15     ORDER BY ord)
 16   WHERE ROWNUM = 1;

       ORD         ID INFO     DATE_DT
---------- ---------- -------- -----------
         1       3481 info     16/10/2010

    If you remove the row 'info', the row where DATE_DT = MAX(DATE_DT) will be chosen:

    SQL> WITH my_table AS (
  2  SELECT 1091 id, 'info5' info, to_date('10/10/2010') date_dt FROM DUAL
  3  UNION ALL SELECT 1239, 'old.info' , to_date('14/09/2010') FROM DUAL
  4  UNION ALL SELECT 1340, 'old.info' , to_date('07/10/2010') FROM DUAL
  5  /*UNION ALL SELECT 3481, 'info'     , to_date('16/10/2010') FROM DUAL*/
  6  UNION ALL SELECT 4134, 'info3'    , to_date('21/01/2011') FROM DUAL)
  7  SELECT * FROM (
  8     SELECT 1 ord, t.*
  9       FROM my_table t
 10      WHERE info = 'info'
 11     UNION ALL
 12     SELECT 2 ord, t.*
 13       FROM my_table t
 14      WHERE date_dt = (SELECT MAX(date_dt) FROM my_table)
 15     ORDER BY ord)
 16   WHERE ROWNUM = 1;

       ORD         ID INFO     DATE_DT
---------- ---------- -------- -----------
         2       4134 info3    21/01/2011
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