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Home/ Questions/Q 499807
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:01:24+00:00 2026-05-13T06:01:24+00:00

I have a table like the following which is basically used to give a

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I have a table like the following which is basically used to “give a name” to a value in a table (this table contains values for a bunch of other tables as well, not just for MYTABLE; I’ve omitted a few irrelevant fields from NAMEVALUEMAP):

NAMEVALUEMAP Table
---------------------
VALUE_  | NAME_
---------------------
0       | ZERO
1       | ONE

I didn’t want to use JOINs so I thought of using Sub-Queries.

Problem is when a value does not exist in the NAMEVALUEMAP table then NULL is shown.
Instead of NULL I want to show the actual value from MYTABLE (MYTABLE has ID field as identity column and contains a few rows):

-- //Fine, prints word 'ZERO' when MYTABLE.ABC is 0
SELECT 
(SELECT NAME_ FROM NAMEVALUEMAP WHERE VALUE_ = (SELECT ABC FROM MYTABLE inner_ WHERE inner_.ID = outer_.ID))
FROM 
MYTABLE outer_

-- //Not Fine, prints NULL (because "999" is not in NAMEVALUEMAP). In this case, MYTABLE.ABC is 999
-- //Want it to print 999 if the value is not in NAMEVALUEMAP
SELECT 
(SELECT NAME_ FROM NAMEVALUEMAP WHERE VALUE_ = (SELECT ABC FROM MYTABLE inner_ WHERE inner_.ID = outer_.ID))
FROM 
MYTABLE outer_

-- //Tried COALESCE, but the error is "Invalid column name 'VALUE_'"
SELECT 
COALESCE((SELECT NAME_ FROM NAMEVALUEMAP WHERE VALUE_ = (SELECT ABC FROM MYTABLE inner_ WHERE inner_.ID = outer_.ID)), ABC)
FROM 
MYTABLE outer_

Also, is there a better way to do this sort of value-to-name mapping?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:01:24+00:00Added an answer on May 13, 2026 at 6:01 am

    I would recomend using a LEFT JOIN (is there any reason you are voidung it?) and ISNULL

    SELECT  ISNULL(NAME_, ABC)
    FROM    MYTABLE m LEFT JOIN
        NAMEVALUEMAP n ON m.ABC = n.VALUE_
    

    Well, in that case you can try

    SELECT  ISNULL((select NAME_ FROM NAMEVALUEMAP WHERE VALUE_ = m.ABC), m.ABC)
    FROM    MYTABLE m
    
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