Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6716765
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T08:46:22+00:00 2026-05-26T08:46:22+00:00

I have a table like this: ID Name ———- 1 john 1 molly 2

  • 0

I have a table like this:

ID    Name
----------
1   john
1   molly
2   greg
2   sean
1   holly
2   mill

What should the SQL Query be to aggregate results like the following:

ID  Name
-------------
1   john/molly/holly
2   greg/sean/mill
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T08:46:22+00:00Added an answer on May 26, 2026 at 8:46 am

    Note: The STUFF function simply removes the leading / from the string returned.

    SELECT t1.id, 
           STUFF((SELECT '/' + t2.name
                    FROM YourTable t2
                    WHERE t1.id = t2.id
                    ORDER BY t2.name
                    FOR XML PATH('')),1,1,'') AS Name
        FROM YourTable t1
        GROUP BY t1.id
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a table like this: name code group john 12 smith 15 how
I have a Table (t) like this t.Name t.Parent t.Id John Bob 1 Frank
I have a SQL 2008 database table like this name score ----------------------- steve 207
Let's say I have a table like this: name | address ------------+---------------- JOHN SMITH
I have an XML field in SQL table like this <Root> <Name>Apollo</Name> <Code>1000</Code> <Code>2000</Code>
In sql server 2005 I have a table like this empno name project --------
I have a table like this: group_id name -------- ---- 1 David 1 John
Let's say I have a table like this: name | score_a | score_b -----+---------+--------
I have a table in mysql like this Name Result T1_09_03_2010 fail T2_09_03_2010 pass
i have a table like this one: -------------------------------- id | name -------------------------------- 1 |

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.