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Editorial Team
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Asked: 2026-05-30T03:26:48+00:00

I have a table of users that I want other users to be able

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I have a table of users that I want other users to be able to search for each other by name. Generally this is easy to a point. However I want users with similar names to show up in order of proximity from one another so lets say therotically I am searching for “Mike” but I don’t know his last name.. What I want my results to show is all the “Mike”‘s in my database starting with the closest one first. I have longitude/latitude for all my users so thats not a problem the problem is the way my query is currently constructed I have to provide a specific range. So I am trying to figure out if theres another way I can construct the query to have no range specified so it will just go from closest to furthest.

Current query looks like

SELECT *,(((acos(sin(($lat*pi()/180)) * sin((`latitude`*pi()/180))+cos(($lat*pi()/180)) * cos((`latitude`*pi()/180)) * cos((($lon - `longitude`)*pi()/180))))*180/pi())*60*1.1515) AS `distance` FROM `memb_geo_locations` HAVING `distance` < $range ORDER BY `distance` ASC"

the flip side to this is also I am likely going to have to form an INNER JOIN with this as the names I’d be searching for are under a different table. where a member_id is the link between the 2 tables. the other table would have
member_id, firstname, lastname
the geo table has
member_id, longitude, latitude, primary

Any idea’s?

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1 Answer

  1. Editorial Team
    SELECT 
  *,
  (((acos(sin(($lat*pi()/180)) * sin((`latitude`*pi()/180))+cos(($lat*pi()/180)) 
    * cos((`latitude`*pi()/180)) 
    * cos((($lon - `longitude`)*pi()/180))))*180/pi())*60*1.1515) AS `distance` 
FROM `memb_geo_locations` 
ORDER BY `distance` DESC

    For the first part of your question just remove the HAVING and ORDER BY DESCending.

    Adding the join should be straightforward enough:

    SELECT 
  *,
  (((acos(sin(($lat*pi()/180)) * sin((`latitude`*pi()/180))+cos(($lat*pi()/180)) 
    * cos((`latitude`*pi()/180)) 
    * cos((($lon - `longitude`)*pi()/180))))*180/pi())*60*1.1515) AS `distance` 
FROM memb_geo_locations 
INNER JOIN members ON members.member_id = memb_geo_locations.member_id
WHERE members.firstname LIKE 'bob or whatever%'
ORDER BY `distance` DESC
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