Question

I have a table – something like:

A|B
1|1
1|2
1|3
2|1
2|3
2|4
2|5
3|5

My query returns the distinct values in A if they coincide with a value in B of 1 or 2 – so

A
1
2

I am trying to also return the original count of the 1’s and 2’s in column A – to get something like

A|Count
1|3
2|4

Is there a simple way to get this count please?
However, the COUNT (A) returns the number of A’s coinciding with the initial WHERE statement:

A|Count
1|2
2|1

Thanks!

Answer 1

Another way:

SELECT a, (SELECT count(*) FROM t t2 WHERE t2.a = t.a) a_count
FROM t
WHERE b IN (1,2)
GROUP BY a