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Home/ Questions/Q 330453
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T09:40:58+00:00 2026-05-12T09:40:58+00:00

I have a table that contains date-time values in this format: START 1/13/2009 7:00:00AM

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I have a table that contains date-time values in this format:

START

1/13/2009 7:00:00AM

END

1/13/2008 2:57:00PM

I use the ‘str to date’ function to convert these into a date-time format.

How do I calculate a difference between them?
And then sum it all up so that it displays in total hours (ie total hours for week is 40:53).

I was trying the timediff function but the results don’t sum.

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  1. Editorial Team
    Editorial Team
    2026-05-12T09:40:58+00:00Added an answer on May 12, 2026 at 9:40 am

    Try looking into UNIX_TIMESTAMP and SEC_TO_TIME.

    You would sum up the differences between the timestamps, then use that value (would be in milliseconds) to get the time:

    SELECT SEC_TO_TIME(time_milis / 1000)
    FROM (
       SELECT SUM(UNIX_TIMESTAMP(date1) - UNIX_TIMESTAMP(date2)) as time_milis
       FROM table
    )
    
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