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Home/ Questions/Q 6866405
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:10:47+00:00 2026-05-27T03:10:47+00:00

I have a table that has a fixed layout of rows. Each row has

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I have a table that has a fixed layout of rows. Each row has unique identifier. When the data is returned from the database it has a different order for the rows in that table. The returned data has the same index that exists in the fixed layout so I can find the matching row in the fixed table. I need to move the rows in the fixed table layout to match the order of rows in the data.

Table Layout:

<table>
    <tr id="a1"><td>Some Value1</td></tr>
    <tr id="a2"><td>Some Value2</td></tr>
    <tr id="a3"><td>Some Value3</td></tr>
    <tr id="a4"><td>Some Value4</td></tr>
    <tr id="a5"><td>Some Value5</td></tr>
</table>

So if the order from the database is a3,a4,a5 I need the table to look like this.

<table>
    <tr id="a3"><td>Some Value1</td></tr>
    <tr id="a4"><td>Some Value2</td></tr>
    <tr id="a5"><td>Some Value3</td></tr>
    <tr id="a1"><td>Some Value4</td></tr>
    <tr id="a2"><td>Some Value5</td></tr>
</table>

Is it possible to move the rows by row index or perhaps if I clone the row, move it to a specific row index and then remove the old row/position with something like this.

var clonedRow = $("#tbl_lp_Forms > tbody > tr[class=" + myformurl + "] ").clone(true);
$('#tbl_lp_Forms tr:first').before(clonedRow);

Hope you can help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:10:47+00:00Added an answer on May 27, 2026 at 3:10 am

    First of all – if you want move row you don’t need to clone it.
    When you select some html element and append/prepend it other place then it will be removed from old position – this is how DOM works.
    So according to html you wrote, when you do this:

    var $table = $('table');
    $table.prepend($('#a3'));
    

    then row with id ‘a3’ will be removed from its old position and placed on the beginning of table.

    If we assume that you have array with order you want to achive:

    var order = ['a3', 'a4', 'a5', 'a1', 'a2']; 
    

    then to sort rows according to this table you have to simply iterate from the last element in this array, get row with current id from table, and place it on the beginning like this:

    var order = ['a3', 'a4', 'a5', 'a1', 'a2']; 
    var $table = $('table');        
    
    for (var i = order.length; --i >= 0; ) {
        $table.prepend($table.find('#' + order[i]));
    }
    

    And when you want to move one row and place in before other:

    var $rowa = $('#a1');
    var $rowb = $('#a5');
    $rowb.insertBefore($rowa);
    
    // or even like this
    $('#a5').insertBefore('#a1');
    
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