I have a table that has this schema:
create table mytable (creation_date timestamp,
value int,
category int);
I want the maximum ocurrence of a value every each hour per category, Only on week days. I had made some progress, I have a query like this now:
select category,foo.h as h,value, count(value) from mytable, (
select date_trunc('hour',
'2000-01-01 00:00:00'::timestamp+generate_series(0,23)*'1 hour'::interval)::time as h) AS foo
where date_part('hour',creation_date) = date_part('hour',foo.h) and
date_part('dow',creation_date) > 0 and date_part('dow',creation_date) < 6
group by category,h,value;
as result I got something like this:
category | h | value | count
---------+----------+---------+-------
1 | 00:00:00 | 2 | 1
1 | 01:00:00 | 2 | 1
1 | 02:00:00 | 2 | 6
1 | 03:00:00 | 2 | 31
1 | 03:00:00 | 3 | 11
1 | 04:00:00 | 2 | 21
1 | 04:00:00 | 3 | 9
1 | 13:00:00 | 1 | 14
1 | 14:00:00 | 1 | 10
1 | 14:00:00 | 2 | 7
1 | 15:00:00 | 1 | 52
for example at 04:00 I have to values 2 and 3, with counts of 21 and 9 respectively, I only need the value with highest count which would be the statiscal mode.
BTW I have more than 2M records
This can be simpler:
Basically these are the steps:
WHERE ...). Use ISODOW to simplify the expression.hourfromtimestampash.category,handvalue.integer– we don’t needbigint.category,hand the highest count (DESC).(category, h)with the accordingcategory.I am able to do this in one query level, because
DISTINCTis applied after the aggregate function.The result will hold no rows for any
(category, h)without no entries at all. If you need to fill in the blanks,LEFT JOINto this: