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Editorial Team
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Asked: 2026-06-15T03:29:02+00:00

I have a table that holds price information. I need to select the max

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I have a table that holds price information. I need to select the max value of every three rows. EXAMPLE:

Table `daily_high`
 ____ _______
| ID | HIGH  |
| 1  | 24.65 |
| 2  | 24.93 |
| 3  | 26.02 |
| 4  | 25.33 |
| 5  | 25.16 |
| 6  | 25.91 |
| 7  | 26.05 |
| 8  | 28.13 |
| 9  | 27.07 |
|____|_______|


Desired output to new table (ID will be auto-increment so don't assume an association exists between this ID 1 and the daily_high ID 1:
 ____ ___________
| ID | 3MaxHIGH  |
|____|___________|
| 1  | 26.02     |
| 2  | 25.91     |
| 3  | 28.13     |
|____|___________|

I want to compare IDs 1,2, and 3 to determine the high value among them. Then once I have compared 1-3, I want to move on to 4 through 6, then 7 through 9, etc until I’ve done this for all values contained in the table (currently about 400,000 values). I have written code that uses

SELECT max(HIGH) FROM daily_high as dh1 JOIN (SELECT max(HIGH) FROM daily_high WHERE id >= dh1 AND id < (dh1.id + 3))

This works but is horribly slow. I’ve tried using the SELECT statement where I identify the column values to be pull for display, meaning between the SELECT and FROM parts of the query.

I’ve tried to use JOIN to join all 3 rows onto the same table for comparison but it too is horribly slow. By slow I mean just under 10 seconds to gather information for 20 rows. This means that the query has analyzed 60 rows (20 groups of 3) in 9.65879893303 seconds (I didn’t make this up, I used microtime() to calculate it.

Anyone have any suggestions for faster code than what I’ve got?

Keep in mind that my actual table is not the same as what I’ve posted above, but it the concept is the same.

Thanks for any help.

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1 Answer

  1. Editorial Team

    Why not to use DIV operator for grouping your aggregation:

    SELECT (id-1) DIV 3 + 1 AS ID, MAX(high) AS 3MaxHIGH 
FROM daily_high 
GROUP BY (id-1) DIV 3

    This query gives the same result.

    ID  3MaxHIGH
1   26.02
2   25.91
3   28.13

    I was unable to run your query, and I believe that this one is faster.

    UPD: To ensure that you have valid groups for your ranges, use this query:

    select id, high, (id-1) div 3 + 1 from daily_high

    result:

    id  high    (id-1) div 3 + 1
1   24.65   1
2   24.93   1
3   26.02   1
4   25.33   2
5   25.16   2
6   25.91   2
7   26.05   3
8   28.13   3
9   27.07   3
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