Question

I have a table users:

id  |   rating
1       4
2       -1
3       12
4       0
5       2
6       0

How I can select user’s place ordering by rating where id = N and that users with similar rating have the same place in the top?

UPD: I want to output:

If userid = 1, his rank is 2, if userid = 2, his rank is 5, if userid = 3, rank is 1, …
But if userid = 4 or 6 their rank are 4 because rates are similar.

Answer 1

I think you want to find the rating for asll user_id’s`:

SELECT id,
       IF(rating <> @var_rating_prev, (@var_rank:= @var_rank + 1), @var_rank) AS rank,
       (@var_rating_prev := rating) AS rating
FROM table_name a,(SELECT @var_rank := 0, @var_rating_prev := 0) r
ORDER BY rating DESC;

Example @ sqlfiddle

If you don’t want to change the order of records in output then try this:

SELECT a.*, b.rank
FROM test_table a
     INNER JOIN (
            SELECT id,
                   IF(rating <> @var_rating_prev, (@var_rank:= @var_rank + 1), @var_rank) AS rank,
                   (@var_rating_prev := rating) AS rating
            FROM test_table a,(SELECT @var_rank := 0, @var_rating_prev := 0) r
            ORDER BY rating DESC
        ) b
         ON a.id = b.id
ORDER BY a.id;