Question

I have a table (users) with various users. if you refer someone to register it creates a referal id in a field (refcode) similar to your (id) in his/her profile. now when he/she is logged in, i want to add value to the referal’s profile.

So basically i need to add value to a user not logged in.

here is my code.

---

$sql="SELECT * FROM users";

$val=(2);
$result=mysql_query($sql,$bd);


$data=mysql_fetch_assoc($result);

while ($array = mysql_fetch_array($result)) {
 // equate the value to a variable to use outside
 // this while loop
 $acc_balance = $array['com_balance'];
 $comm = $array {$_SESSION['refcode']};
 $commision = $array['id'];
 }

 $remainder = $acc_balance + $val;

 $update_query = mysql_query("UPDATE users SET com_balance = '".      mysql_real_escape_string($remainder) ."'
 WHERE id=refcode");

if ($update_query) {
print ""

Answer 1

A bunch of changes, marked by numbers:

   $sql="SELECT * FROM users where userID='$_SESSION['refcode']'"; //#1

   $val = 2; //#2 : Why do u need the ()?
   $result = mysql_query($sql,$bd);

   $data=mysql_fetch_assoc($result);

   while ($array = mysql_fetch_array($result)) {
  // equate the value to a variable to use outside
  // this while loop
   $acc_balance = $array['com_balance'];
   $comm = $array{$_SESSION['refcode']}; //#3: I am not sure what you're doing here? 
   $commision = $array['id'];
   }

   $remainder = $acc_balance + $val;       

   $update_query = mysql_query("UPDATE users SET com_balance = '".              mysql_real_escape_string($remainder) ."'
   WHERE id=refcode"); // #4: where are you defining refcode? if variable, the query needs to be WHERE id='$refcode'");

   if ($update_query) {
     print "Update successful";