Question

I have a table view with 4 rows and at the bottom of the table view footer for the table I need to display an URL link. It should open the corresponding web page.

For example I need to have a link named “Search using web” and this link should take the view to http://www.google.com. How can I implement this?

Answer 1

Firstly You add UITextView in each row of table view

textView.text = @"Search using web";
textView.dataDetectorTypes = UIDataDetectorTypeLink;

Open On The safari use this code….

NSURL *url = [ [ NSURL alloc ] initWithString: @"http://www.google.com" ];
[[UIApplication sharedApplication] openURL:url];
[url release];

any Help use this IOS Refernce