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Home/ Questions/Q 505851
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:38:27+00:00 2026-05-13T06:38:27+00:00

I have a Table where Parent Child Relation ship is stored as: ChildID Name

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I have a Table where Parent Child Relation ship is stored as:
ChildID Name ParentID
1 A1 Null
2 A2 1
3 B1 Null
4 A3 2
5 A4 1
I m Woking on Objective C and I need to Generate a text File in Manner:
Name =A1>
Name =A2>
Name =A3/>
Name =A2/>
Name =A4/>
Name =B1/>

I was using a approch where I catch the Last Element (Id=5) first and then checking all other nodes to get its Parent Nodes. n Complexity comes to be as n*n-1, Is there any other better approach as this approach is not a succes when we have lasrge data in Database.

Database Structure is flexible, we can change that, if there is something better…

Looking for your help and support.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:38:28+00:00Added an answer on May 13, 2026 at 6:38 am

    From your output structure, I assume your data represents a tree. You therefore have a simple “get all children of a node” request as SELECT childId, name FROM tree WHERE parentId = ?, which lets you perform a standard tree traversal. Pseudocode:

    def displayNode(node)  
      children = selectChildren(node.id)
      if (empty(children)) 
        print '<'+node.name+'/>'
      else 
        print '<'+node.name+'>'
        for (child in children) 
          displayNode(child)
        print '</'+node.name+'>'
    

    An optimization, if running one query per node is too much (which probably is the case) is to run a single query to fetch all the data and place it in an optimized data structure:

    for (node in selectAllNodes())
      nodes[node.parent].append(node);
    
    def selectChildren(id)
      return nodes[id]
    
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