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Home/ Questions/Q 8406227
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T23:02:59+00:00 2026-06-09T23:02:59+00:00

I have a table which has a DATETIME column called dtInsertDate . The value

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I have a table which has a DATETIME column called dtInsertDate.

The value in this column is '2012-08-10 22:48:41.047'. I know that this date is 10th August 2012.

I want to run the following SELECT statement to retrieve this row:

select *
from myTable
where dtinsertdate = '2012-08-10 22:48:41.047'

The puzzling thing is, if I run this SELECT when the option dateformat is mdy, it finds that row.

If I run it on another copy of the database when the option dateformat is dmy, the SELECT doesn’t return anything.

Why is this ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T23:03:01+00:00Added an answer on June 9, 2026 at 11:03 pm

    The reason is that dmy causes your string literal to be interpreted as day first – so that is October 8th instead of August 10th.

    The solution is to always use an unambiguous format for date literals (or to use properly typed parameters instead of dealing with translating from a string in the first place).

    WHERE dtinsertdate = '20120810 22:48:41.047';
    

    As you’ve discovered, those dashes in your date can make the actual value be interpreted differently depending on language / dateformat settings.

    Another alternative is to keep the dashes but to inject a T instead of a space, e.g.:

    WHERE dtinsertdate = '2012-08-10T22:48:41.047';
    

    Your original is more readable, but it’s only guaranteed to work if you make the language and dateformat fixed (for example try with SET LANGUAGE FRENCH;). Try this experiment:

    SET DATEFORMAT DMY;
    DECLARE @d DATETIME = '2012-08-10 22:48:41.047'
    SELECT MONTH(@d);
    GO
    
    SET LANGUAGE FRENCH;
    DECLARE @d DATETIME = '2012-08-10 22:48:41.047'
    SELECT MONTH(@d);
    GO
    
    SET DATEFORMAT MDY;
    DECLARE @d DATETIME = '2012-08-10 22:48:41.047'
    SELECT MONTH(@d);
    GO
    
    SET DATEFORMAT MDY;
    SET LANGUAGE ENGLISH;
    DECLARE @d DATETIME = '2012-08-10 22:48:41.047'
    SELECT MONTH(@d);
    GO
    

    Sometimes the result is 8, sometimes the result is 10. Now try it again with one of the two formats I suggest above – result is always 8.

    I have lots of juicy details worthy of reading here:

    • Bad habits to kick : mis-handling date / range queries

    But for the specific problem you’re talking about, always, always, always use one of the following formats for date/time literals, I don’t consider any others safe.

    For date + time:

    YYYY-MM-DDTHH:MM:SS...
    YYYYMMDD HH:MM:SS...
    

    For date only:

    YYYYMMDD
    
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