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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:46:46+00:00 2026-05-15T03:46:46+00:00

I have a table which has a foreign key referencing itself. This would be

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I have a table which has a “foreign key” referencing itself. This would be very useful, except I am uncertain how to add the first record to such a table. No matter what I add, I cannot provide a valid “foreign” key to the table itself, having no entries yet. Maybe I’m not going about this correctly, but I want this table to represent something that is always a member of itself. Is there a way to “bootstrap” such a table, or another way to go about self-reference?

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:46:47+00:00Added an answer on May 15, 2026 at 3:46 am

    One option is to make your field NULL-able, and set the root record’s parent key to NULL:

    CREATE TABLE tb_1 (
       id       int   NOT NULL  PRIMARY KEY,
       value    int   NOT NULL,
       parent   int   NULL,
       FOREIGN KEY (parent) REFERENCES tb_1(id)
    ) ENGINE=INNODB;
    Query OK, 0 rows affected (0.43 sec)
    
    -- This fails:
    INSERT INTO tb_1 VALUES (1, 1, 0);
    ERROR 1452 (23000): A foreign key constraint fails.
    
    -- This succeeds:
    INSERT INTO tb_1 VALUES (1, 1, NULL);
    Query OK, 1 row affected (0.08 sec)
    

    Otherwise you could still use a NOT NULL parent key and point it to the root record itself:

    CREATE TABLE tb_2 (
       id       int   NOT NULL  PRIMARY KEY,
       value    int   NOT NULL,
       parent   int   NOT NULL,
       FOREIGN KEY (parent) REFERENCES tb_2(id)
    ) ENGINE=INNODB;
    Query OK, 0 rows affected (0.43 sec)
    
    -- This fails:
    INSERT INTO tb_2 VALUES (1, 1, 0);
    ERROR 1452 (23000): A foreign key constraint fails.
    
    -- This succeeds:
    INSERT INTO tb_2 VALUES (1, 1, 1);
    Query OK, 1 row affected (0.08 sec)
    
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