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Home/ Questions/Q 8191321
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T03:53:34+00:00 2026-06-07T03:53:34+00:00

I have a table which has two columns (id and word). I have an

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I have a table which has two columns (id and word). I have an other table which has a data column and its value references the word in the first table. Here is a sample code:

CREATE TABLE `words` (
  `id` TINYINT,
  `word` VARCHAR(50),
  PRIMARY KEY (`id`)
);

INSERT INTO `words` VALUES (1, 'one'), (2, 'two'), (3, 'three');

CREATE TABLE `data` (
  `data` TEXT
);

INSERT INTO `data` VALUES ('foo=bar\nword=one'), ('word=three');

I would like to replace the references of words to ids. So word=one would become word=1, word=three would become word=3 and so on. I tried this query, but it doesn’t work:

UPDATE `data`, `words` SET `data`.`data` = REPLACE(`data`.`data`, CONCAT('word=', `words`.`word`), CONCAT('word=', `words`.`id`));

Any suggestion or idea how to achieve what I want? Thanks!

Edit: Forgot to mention that data column is in INI format, so other key-value pairs can be in fields too. Adjusted the example.

Edit: Thanks to the idea of @nortphole I managed to build the query that I need:

UPDATE `data` SET `data`.`data` = REPLACE(`data`.`data`, CONCAT('word=', SUBSTRING_INDEX(SUBSTRING_INDEX(`data`.`data`, 'word=', -1), '\n', 1)), CONCAT('word=', (SELECT `id` FROM `words` WHERE `words`.`word` = SUBSTRING_INDEX(SUBSTRING_INDEX(`data`.`data`, 'word=', -1), '\n', 1))));
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  1. Editorial Team
    Editorial Team
    2026-06-07T03:53:35+00:00Added an answer on June 7, 2026 at 3:53 am

    Try something like this:

    UPDATE data 
       SET data = CONCAT('word=',(SELECT id 
                                    FROM words 
                                   WHERE words.word = SUBSTRING_INDEX(data.data,'=',-1)))
    

    Sorry, I don’t have MySql here to test it out (sepcifically make sure the SUBSTRING is getting everything after ‘word=’)

    EDIT:
    I use substring_index with a -1 to get me the last index of the = sign.

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