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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T18:12:49+00:00 2026-05-22T18:12:49+00:00

I have a table which in my opinion will benefit from partitioning: CREATE TABLE

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I have a table which in my opinion will benefit from partitioning:

CREATE TABLE [dbo].[my_table](
[id] [int] IDENTITY(1,1) NOT NULL,
[external_id] [int] NOT NULL,
[amount] [money] NOT NULL,
    PRIMARY KEY CLUSTERED ([id] ASC));

There are just few different external_id and thousands of records for each of them.
SSMS Create Partition Wizard generates a script that I don’t completely understand. After creating partition function and partition schema,
–it drops Primary Key,
–then creates Primary Key again on id, this time as non-clustered,
–then creates clustered index on external_id on newly created partition schema,
–and finally it drops the clustered index created on previous step.

Everything except last step seems clear, but I cannot get why it has to drop the clustered index. Should I remove the last step from the batch?

Any help will be greatly appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-22T18:12:50+00:00Added an answer on May 22, 2026 at 6:12 pm

    It makes sense.

    The partition key is going to be the external id, so the clustered index must include that.

    It preserves the primary key in a non-clustered index – since it’s on ID not external_id

    It created the clustered index on external_id to physically move the data into the partition scheme.

    It drops the clustered index since it only used it to move the data – it was not a previously specified index.

    There are a number of alternatives, assuming you always know the external_id, then you could choose to create the clustered index as (id,external_id) – the partition schema / function field used for the table must be within the clustered index on the partition schema.

    Performance wise, this is not going to be a huge boost, the use of it is more that you can drop an entire external_id trivially, instead of a large delete transaction.

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