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Home/ Questions/Q 8155911
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T16:48:07+00:00 2026-06-06T16:48:07+00:00

I have a table which looks like this: mysql> SHOW COLUMNS FROM Users; +————+————–+——+—–+———+—————-+

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I have a table which looks like this:

mysql>  SHOW COLUMNS FROM Users;
+------------+--------------+------+-----+---------+----------------+
| Field      | Type         | Null | Key | Default | Extra          |
+------------+--------------+------+-----+---------+----------------+
| user_id    | int(10)      | NO   | PRI | NULL    | auto_increment |
| username   | varchar(50)  | YES  |     | NULL    |                |
| password   | varchar(255) | YES  |     | NULL    |                |
| email      | varchar(255) | YES  |     | NULL    |                |
| phone      | varchar(255) | YES  |     | NULL    |                |

I am trying to create a new table like this:

create table jobs (id int,  FOREIGN KEY (user_id) REFERENCES Users(user_id)) ENGINE=INNODB;

But I am getting this error:

ERROR 1072 (42000): Key column 'user_id' doesn't exist in table

I am sure I am missing something very basic.

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  1. Editorial Team
    Editorial Team
    2026-06-06T16:48:09+00:00Added an answer on June 6, 2026 at 4:48 pm

    Try this:

    create table jobs (
        id int,  
        user_id int,
        FOREIGN KEY (user_id) REFERENCES Users(user_id)
    ) ENGINE=INNODB;
    

    The first user_id in foreign key constraint refers to the table where the contraint is defined and the second refers to the table where it is pointing to.
    So you need a field user_id in your jobs table, too.

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