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Home/ Questions/Q 8391367
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T19:14:32+00:00 2026-06-09T19:14:32+00:00

I have a table which stores categories and sub categories (self join) The table

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I have a table which stores categories and sub categories (self join)

The table structure is like this:
-CategoryId
-CategoryName
-ParentCategoryId

How to find nth child/childs of a category in sql query

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T19:14:33+00:00Added an answer on June 9, 2026 at 7:14 pm

    How about something like this

    DECLARE @Categories TABLE(
            CategoryId INT, 
            CategoryName VARCHAR(20),
            ParentCategoryId INT
    )
    
    INSERT INTO @Categories SELECT 1, '1',NULL
    INSERT INTO @Categories SELECT 2, '2',NULL
    
    INSERT INTO @Categories SELECT 3, '1.3',1
    INSERT INTO @Categories SELECT 4, '1.4',1
    
    INSERT INTO @Categories SELECT 5, '1.3.5',3
    INSERT INTO @Categories SELECT 6, '1.3.6',3
    INSERT INTO @Categories SELECT 7, '1.3.6.7',6
    
    INSERT INTO @Categories SELECT 8, '1.4.8',4
    
    DECLARE @CatID INT,
            @NthLevel INT
    SELECT  @CatID = 1,
            @NthLevel = 2
    
    ;WITH Vals AS (
            SELECT  *,
                    1 AS CatLevel
            FROM    @Categories c 
            WHERE   CategoryId IS NULL
            UNION ALL
            SELECT  c.*,
                    CatLevel + 1 AS CatLevel
            FROM    Vals v INNER JOIN
                    @Categories c   ON  c.ParentCategoryId =  v.CategoryID
    )
    SELECT  *
    FROM    Vals
    WHERE   CatLevel = @NthLevel
    

    This will recursively build the tree structure, and limit it on the tree level you are looking for.

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