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Home/ Questions/Q 6191399
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T02:45:26+00:00 2026-05-24T02:45:26+00:00

I have a table with 2 columns, Ex_Id and Term_Id, both int type. My

  • 0

I have a table with 2 columns, Ex_Id and Term_Id, both int type. My table will have many Term Ids for one Exercise Id.

     Table would look like this:
      Ex_Id Term_Id
         1     2
         1     3
         1     4
         1     5
         2     2
         3     2
         3     4

etc. Getting a list of Ex_Id is the primary requirement. My function would be like this.

List<int> Get_ExId_List(List<int> lst_TermId)
{
    // return a list of Ex_Id <int>
}

That is, I’ll be passing a list of Term Ids and I need to get a list of Exercise Ids back matching some criteria. The criteria to select can be better explained with this pseudo-code: SELECT such Ex_Ids FROM table Exercise_Term WHERE Ex_Id has all the corresponding Term_Ids in the lst_TermId

For eg, from the sample table I provided above,

List<int> Get_ExId_List([2])
{
    // return [1,2,3]
}

List<int> Get_ExId_List([2,4])
{
    // return [1,3]
}

List<int> Get_ExId_List([2,3,4])
{
    // return [1]
}

Query part is my confusion. What would be the query in this condition like? Rest I can manage. Hope question is clear. Thanks..

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T02:45:27+00:00Added an answer on May 24, 2026 at 2:45 am
    SELECT Ex_ID 
    FROM TableName 
    WHERE Term_ID IN (?, ?, ?)                --- (2, 3, 4)
    GROUP BY Ex_ID
    HAVING COUNT(DISTINCT Term_ID) = 3        --- number of terms in the above list
    

    If the combination (Ex_ID, Term_ID) is unique in the table, you can replace COUNT(DISTINCT Term_ID) with COUNT(*)

    This is a relational division problem. The “standard” solution would be using two negatives (NOT EXISTS):

    SELECT DISTINCT Ex_ID
    FROM TableName e
    WHERE NOT EXISTS
            ( SELECT *
              FROM TableName t
              WHERE t.Term_ID IN (?, ?, ?)           --- the list of terms
                AND NOT EXISTS
                      ( SELECT *
                        FROM TableName a
                        WHERE a.Term_ID = t.Term_ID
                          AND a.Ex_ID = e.Ex_ID
                      )
            ) 
    

    or better in your case:

    SELECT DISTINCT Ex_ID
    FROM TableName e
    WHERE NOT EXISTS
            ( SELECT *
              FROM
                ( SELECT ? AS Term_ID  
                UNION
                  SELECT ?
                UNION 
                  SELECT ?
                ) AS t
              WHERE NOT EXISTS
                      ( SELECT *
                        FROM TableName a
                        WHERE a.Term_ID = t.Term_ID
                          AND a.Ex_ID = e.Ex_ID
                      )
            ) 
    

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