Question

I have a table with 2 primary keys (so the combination of both of them should be unique). The schema is like this:

TABLE="INVOICE_LOGS"
INVOICE_NUMBER  PK  non-null
INVOICE_TYPE    PK  non-null
AMOUNT  

When I try to persist multiple records at a time, I get this hibernate exception:

Caused by:
javax.persistence.PersistenceException:
org.hibernate.NonUniqueObjectException:
a different object with the same
identifier value was already
associated with the session:
[…InvoiceLog#110105269]

So if I use the following code below, I get the hibernate exception above. It works fine if I only persist one record but fails if I try to persist a collection like what I’m trying to do.

    List<InvoiceLog> logs = getLogs();
    for(OvercounterLogDO log: logs) {
        persist(log);
    }

    public void persist(final Object entity) {
        entityManager.persist(entity);
        entityManager.flush();
    }

The hibernate mapping class is below:

@Component(InvoiceLog.BEAN_NAME)
@Scope(BeanDefinition.SCOPE_PROTOTYPE)
@Entity
@Table(name = "INVOICE_LOGS", uniqueConstraints = {@UniqueConstraint(columnNames = "INVOICE_NUMBER"),@UniqueConstraint(columnNames = "INVOICE_TYPE")} ) 
public class InvoiceLog implements java.io.Serializable {

    private static final long serialVersionUID = -7576525197897271909L;

    protected static final String BEAN_NAME = "invoiceLog";

    private long invoiceNumber;
    private String invoiceType;
    private Double amount;

    public InvoiceLog(){}

    public InvoiceLog(Integer invoiceNumber, String invoiceType,
            Double amount) {
        super();
        this.invoiceNumber = invoiceNumber;
        this.invoiceType = invoiceType;
        this.amount = amount;
    }

    @Id
    @Column(name = "INVOICE_NUMBER", unique = true, nullable = false, precision = 10, scale = 0)
    public long getInvoiceNumber() {
        return invoiceNumber;
    }
    public void setInvoiceNumber(long invoiceNumber) {
        this.invoiceNumber = invoiceNumber;
    }

//  @Id
    @Column(name = "INVOICE_TYPE", nullable = false, length = 4)
    public String getInvoiceType() {
        return invoiceType;
    }
    public void setInvoiceType(String invoiceType) {
        this.invoiceType = invoiceType;
    }

    @Column(name = "AMOUNT", nullable = false, length = 12)
    public Double getAmount() {
        return amount;
    }
    public void setAmount(Double amount) {
        this.amount = amount;
    }

}

Answer 1

Your current mapping has a single Id, invoiceNumber, not a compound key. As such, it’ll demand that the invoiceNumber be unique, not the combination you want. That’s what the exception is telling you, it’s noticing you’re trying to save a second record with the same Id value.

You need to map the two fields as a composite key. It looks from your commenting out the second @Id that you were going in that direction at some point. Here’s the documentation on methods for mapping the composite key.