Question

I have a table with an index and I am executing a aggregate SQL query using sum
you can see what I am doing here in sqlfiddle.

Create table TX (
  i int NOT NULL PRIMARY KEY,
  x1 DECIMAL(7,3), 
  x2 DECIMAL(7,3), 
  x3 DECIMAL(7,3)
);


INSERT INTO TX (i,x1,x2,x3) values
(1,5, 6,6) ;
INSERT INTO TX (i,x1,x2,x3) values
(2,6, 7, 5);
INSERT INTO TX (i,x1,x2,x3) values
(3,5, 6, 7) ;
INSERT INTO TX (i,x1,x2,x3) values
(4,6, 7, 4);

My question is How can I insert into 3 different tables the results of that query?

SELECT SUM(1),
       SUM(x1),SUM(x2),SUM(x3),
       SUM(x1*x1),
       SUM(x2*x1),SUM(x2*x2),
       SUM(x3*x1),SUM(x3*x2),SUM(x3*x3)

FROM TX

so

how can I get something like

Sum(1)
-----
n

index  Sums
------------
1      4
2      22
3      26

index1  index2   Mult
----------------------
1            1   122
2            1   144
2            2   170
3            1   119
3            2   141
3            3   126

Instead of

    SUM(1) SUM(X1) SUM(X2) SUM(X3) SUM(X1*X1) SUM(X2*X1) SUM(X2*X2) SUM(X3*X1) SUM(X3*X2)  SUM(X3*X3)
_____________________________________________________________________________________________________
        4      22       26     22        122        144       170      119          141          126

Answer 1

SELECT SUM(1)
FROM TX;

SELECT 1, SUM(x1)
FROM TX
UNION ALL 
SELECT 2, SUM(x2)
FROM TX
UNION ALL 
SELECT 3, SUM(x3)
FROM TX;

SELECT a.x i1, b.x i2, SUM(a.s * b.s)
FROM
(
    SELECT i, 1 x, x1 s
    FROM TX
    UNION ALL 
    SELECT i, 2 x, x2 s
    FROM TX
    UNION ALL 
    SELECT i, 3 x, x3 s
    FROM TX
) a
INNER JOIN
(
    SELECT i, 1 x, x1 s
    FROM TX
    UNION ALL 
    SELECT i, 2 x, x2 s
    FROM TX
    UNION ALL 
    SELECT i, 3 x, x3 s
    FROM TX
) b ON a.i = b.i AND a.x >= b.x
GROUP BY a.x, b.x;

SQL Fiddle using your data – Note that your data’s sums (second query) do not match those in your question. I trust this is a typo.

Notice I got a bit lazy with the third query. Instead of writing out the expansion I flattened the table first and joined it on itself.

Also note that in the first query SUM(1) can be replaced with COUNT(*).