Question

I have a table with columns Id,DoucmentId,Name,Created,MinorVersion,MajorVersion

with example data :

GUID,1,'document1',GETDATE(),1,0)
GUID,1,'document1',GETDATE(),2,0)
GUID,1,'document1',GETDATE(),1,1)
GUID,2,'document2',GETDATE(),1,0)

In query i need get all unique with higest major and minor version :

GUID,1,'document1',GETDATE(),1,1)
GUID,2,'document2',GETDATE(),1,0)

I have this query, but i need return all column in table…

SELECT DISTINCT 
          DocumentId,
          MAX(MajorVersion),
          MAX(MinorVersion)
FROM ComDoc_Document
GROUP BY(DocumentId)

Is here some trick to get this?

Thanks for help

EDIT : My configuration is MSSQL 2008R2 standart

Answer 1

SELECT Id,DocumentId,Name,Created,MinorVersion,MajorVersion
FROM
(
SELECT *
    ,RANK() OVER 
    (PARTITION BY DocumentID ORDER BY MajorVersion DESC, MinorVersion DESC) AS 'RANK'
FROM ComDoc_Document
) tmp
WHERE RANK = 1

this also has the advantage that if you later decide to retrieve the last two revisions for each document, you just do WHERE RANK <= 2