Question

I have a table with the fields timeout and timein. I need to return a list of records where timeout is on a different day to timein. How can I achieve this?

Answer 1

If both dates are in the same month, then:

select * 
from table 
where DAY(timeout) <> DAY(timein0) 

or

select * 
from table 
where DATEPART(day,timeout) <> DATAPART(day,timein) or

will work..

If, however, they can be in different months, then you need to compare the full dates. This should do that for you:

select *
from table
where DATEDIFF(day,timeout,timein) <> 0