Question

I have a table with the following data:

client   totalA     totalB   item#
clientA 454265.08   869.5   307-1-3138
clientA 1110067.09  869.5   307-1-3138
clientB 15900       852.5   307-1-3149
clientC 436450.76   465     307-5-680
clientC 1066535.03  465     307-5-680

Notice that there are 2 rows for clientA and clientC, because the totalA column is different – because the amounts are displayed in 2 currencies – . What I need to return is 2 rows per currency, but the second row should only show the totalA column, and blank for the rest. So what I want is:

  client   totalA      totalB   item#
clientA 454265.08    869.5    307-1-3138
           1110067.09                  
clientB 15900        852.5    307-1-3149
clientC 436450.76    465      307-5-680
           1066535.03                         

Any suggestions how to do this in SQL Server 2008?

Thanks!

Answer 1

SELECT Client, totalA, case when number = 1 then totalb else null end totalB, case when number = 1 then item else null end Item 
FROM (
    select *, row_number() over(partition by client order by client) number 
    from Clients 
) A