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Home/ Questions/Q 8205303
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T08:11:09+00:00 2026-06-07T08:11:09+00:00

I have a table with trs that look like this. <tr> <td><a href=http://www.mysite.com>Link</a></td> <td>value

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I have a table with trs that look like this.

<tr> 
  <td><a href="http://www.mysite.com">Link</a></td>
  <td>value 2</td>
  <td>value 3</td>
  <td>value 4</td>
  <td>value 5</td>
</tr>

I’m using xPath to select all <tr> and looping through them.

foreach($xpathResult as $item){
  //print the href of the first td
  //print the nodeValue of the second td
  //print the nodeValue of the 3rd td
  //print the nodeValue of the 4th td
  //print the nodeValue of the 5th td
}

How do I print the href of the first td and the nodeValue of each td thereafter? There’s firstChild and lastChild, but how do I get to the middle s? I could use firstChild->nextSibling and firstChild->nextSibling->nextSibling but isn’t there an easier way?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T08:11:13+00:00Added an answer on June 7, 2026 at 8:11 am

    Just use a loop on childNodes, like so:

    foreach( $trs as $tr) {
        echo $tr->firstChild->firstChild->attributes->getNamedItem( 'href')->value;
        foreach( $tr->childNodes as $k => $td) {
            if( $k == 0) continue; // Skip the first one
            echo $td->nodeValue . "\n";
        }
    }
    
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