Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6081645
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T11:11:57+00:00 2026-05-23T11:11:57+00:00

I have a table with two column as : serial_number 1 2 3 dateOfAppoinement

  • 0

I have a table with two column as :

serial_number
1
2
3

dateOfAppoinement
2011-06-30 00:39:04.130
2011-06-30 00:40:01.130
2011-06-30 00:49:04.130

I want to get the highest serial_number of a day. I have to avoid the time part. I’m just using the date part.

Can anyone tell me how can I do this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T11:11:58+00:00Added an answer on May 23, 2026 at 11:11 am

    I updated my answer to use Convert like snkmchnb suggested. However in SQL Server 2008 there is a DATE datatype that is just the date portion of the year so you don’t have to specify the 120 code. I tested this and it works perfectly and the SQL is pretty straight forward.

    SELECT
        MAX(serial_number),
        CONVERT(DATE, dateOfAppointment) as [Day]
    FROM
        #TempSerialsByDate
    GROUP BY
        CONVERT(DATE, dateOfAppointment)
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a table with two columns: latitude and longitude. I want to get
I have a simple two column table; I want a way to align the
I want to have one table with two TIMESTAMP columns. One column to keep
I have a table with two columns. I want to center the right-most column
I have a table with two columns: column A column B 1 2 1
I have an application in which I'm currently using a two column table in
I have a two-column primary key on a table. I have attempted to alter
I have a table which has two varchar(Max) columns Column 1 Column 2 -----------------------
Say I have an MSSQL table with two columns: an int ID column that's
I have a table with a column event_time . How can I select two

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.