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Home/ Questions/Q 7038029
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:37:12+00:00 2026-05-28T01:37:12+00:00

I have a table with user info called ‘a’ and a table with data

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I have a table with user info called ‘a’ and a table with data from different API’s (twitter,foursquare) which in the example, based on the value
of the a.api_type should become b. What I want in the end is to be able to grab the right avatar from the active API (either api_foursquare or api_twitter).

I have been trying to get this to work with this query for a while, but I keep getting this error. Sql is not my strongest point, so any tips on how to fix this would be great 🙂

  "[Err] 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near

  INNER JOIN b ON b.user_id = a.user_id  at line 11"

SELECT a.user_id, 
       a.api_type, 
       b.avatar, 
       b.user_id
(CASE
       WHEN a.api_type = 0 THEN api_foursquare
       WHEN a.api_type = 1 THEN api_twitter
END) as b
FROM a WHERE a.cookie_hash = :cookie_hash
INNER JOIN b ON b.user_id = a.user_id

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:37:13+00:00Added an answer on May 28, 2026 at 1:37 am

    You cannot pick a table to join in a case statement. You should left-join to both tables, and then pick the value from one of them in the case statement, like this:

    SELECT a.user_id, 
           a.api_type,
           (case WHEN a.api_type = 0 THEN b.avatar ELSE c.avatar END) as avatar,
           (case WHEN a.api_type = 0 THEN b.user_id ELSE c.user_id END) as user_id
    FROM a 
      LEFT OUTER JOIN api_foursquare b ON b.user_id = a.user_id
      LEFT OUTER JOIN api_twitter c ON c.user_id = a.user_id
    WHERE a.cookie_hash = :cookie_hash
    

    You probably do not need the last expression (the ...as user_id one), because it is going to be equal to a.user_id if there is a row in either api_twitter or api_foursquare that matches a.user_id.

    You also have to put the WHERE clause after the FROM clause:

    EDIT: Taking into account ypercube’s great suggestion, the query would look like this:

    SELECT a.user_id, 
           a.api_type,
           COALESCE(b.avatar, c.avatar) as avatar
    FROM a 
      LEFT OUTER JOIN api_foursquare b ON b.user_id = a.user_id AND a.api_type = 0
      LEFT OUTER JOIN api_twitter c ON c.user_id = a.user_id and a.api_type = 1
    WHERE a.cookie_hash = :cookie_hash
    
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