Question

I have a tableview in a ViewController defined in storyboard. the tableview has prototype cells. i want that when user touches the cell then a url should open in external safari of iphone. how to achieve that?
from where i have to invoke the following line:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:siteURL]]; 

Answer 1

In the class of which an instance is set to the table view’s delegate:

- (void)tableView:(UITableView *)tv didSelectRowAtIndexPath:(NSIndexPath *)ip
{
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:siteURL]];
}