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Home/ Questions/Q 8093109
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T20:25:59+00:00 2026-06-05T20:25:59+00:00

I have a template class, called OneCell , here the definition: template <class T>

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I have a template class, called OneCell, here the definition:

template <class T>
class OneCell
{
.....
}

I have a cast operator from OneCell to T, here

operator T() const
{
    getterCount++;
    return value;
}

As you see, I want to increment variable in this method, but i get an error because the keyword const.

On the other hand, if I remove this keyword, the casting doesn’t work at all.

What can I do?

Thank you, and sorry about my poor English.

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  1. Editorial Team
    Editorial Team
    2026-06-05T20:26:00+00:00Added an answer on June 5, 2026 at 8:26 pm

    Actually operator T() const is a const-member function, inside which this pointer refers to a const object, which in turns makes the getterCount const as well.

    The solution is to declare getterCount as mutable, as shown below:

    mutable size_t getterCount;
    

    Now getterCount can be incremented in const member function, which also means, it can be incremented even if the object is const:

    void f(OneCell const & cell)
    {
        //incrementing getterCount!
        ++cell.getterCount; //ok, even though cell is const!
    }
    
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