Question

I have a test I have to use regularly in queries to see if a CPT billing code is a billable encounter. In the SQL query, the test looks like this:

where (pvp.code between '99201' and '99215'
    or pvp.code between '99221' and '99239')

plus a whole bunch more ranges.

I tried to create a function by just plugging this in to the function, but I got an “incorrect syntax” error — not a huge surprise, really.

CREATE FUNCTION IsEncounter 
(
    @code varchar(20)
)
RETURNS bit
AS
BEGIN
    DECLARE @Result bit;

    SELECT @Result = @code between '99201' and '99215'
            or @code between '99221' and '99239';

    -- Return the result of the function
    RETURN @Result;

END

I suppose I can do something like

if (@code >= '99201' and @code <= '99215')
        or (@code >= '99221' and @code <= '99239')
    select @Result = 1
else
    select @Result = 0;

but I’d like to know the cleanest way to do this. Thanks.

Answer 1

Something like this should work:

CREATE FUNCTION IsEncounter 
(
   @code varchar(20)
)
RETURNS bit
AS
BEGIN
    DECLARE @Result bit

    SET @Result = CASE WHEN (@code between '99201' and '99215') or (@code between '99221' and '99239') THEN 1 ELSE 0 END

    RETURN @Result
END