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Home/ Questions/Q 269841
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T23:54:08+00:00 2026-05-11T23:54:08+00:00

I have a test winforms app with ThreadExceptionHandler that displays a message box when

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I have a test winforms app with ThreadExceptionHandler that displays a message box when an unhandled exception is caught, as follows:

[STAThread]
static void Main()
{
    Application.ThreadException += new System.Threading.ThreadExceptionEventHandler(Application_ThreadException);
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Application.Run(new Form1());
}

static void Application_ThreadException(object sender, System.Threading.ThreadExceptionEventArgs e)
{
    MessageBox.Show("error caught");
}

When I force an error in the ctor of Form 1 (e.g. dividebyzero) as follows:

public Form1()
{
     InitializeComponent();

     int i = 0;
     int x = 5 / i;
}

and run the app outside of Visual Studio (in Windows 7), the divide by zero exception is not handled – I get an unhelpful “WindowsFormApplication1 has stopped working…” message.

However, when I move the dividebyzero exception to the Form1_Load event and rerun, the exception is handled properly.

Can someone explain why this is the case? The reason I ran this test program is because I am experiencing a similar unhandled exception issue in another, enterprise app that I am trying to track down.

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  1. Editorial Team
    Editorial Team
    2026-05-11T23:54:09+00:00Added an answer on May 11, 2026 at 11:54 pm

    This is probably due to the fact that the constructor is executed before Application.Run() is called. Your code could also be written as

    [STAThread]
    static void Main()
    {
        Application.ThreadException += new System.Threading.ThreadExceptionEventHandler(Application_ThreadException);
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        Form1 MyForm = new Form1();
        Application.Run(MyForm);
    }
    

    Your thread exception handler only becomes active when Application.Run() is executing. In order to catch exceptions in the form constructor, you need to surround Form1 MyForm = new Form1(); witch a seperate try/catch block.

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