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Home/ Questions/Q 413539
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T18:11:39+00:00 2026-05-12T18:11:39+00:00

I have a text document like so: <table width=10> </table> I open the document

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I have a text document like so:

<table width="10">
</table>

I open the document with the VI editor. I want to replace all instances of width=”somenumber” with nothing. I issue this command in the VI editor:

:0,$s/width="[\d]+"//gc

VI says no pattern found. I also tried this and it doens’t work:

0,$s/width="[0-9]+"//gc

This one below worked:

:0,$s/width="\d\d"//gc

What’s wrong with my first two expressions?

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  1. Editorial Team
    Editorial Team
    2026-05-12T18:11:39+00:00Added an answer on May 12, 2026 at 6:11 pm

    You have two errors in your regexp!

    First, use \d without []s around it. You probably mix it with character classes like :alpha:, :digit:, etc.

    Second, Escape the + sign. By default you should escape it.

    So your regexp would be:

    :0,$s/width="\d\+"//gc
    

    And, please, read help before posting on stackoverflow:

    :h :s
    

    You may also be interested in this help section:

    :h magic 
    
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