Question

I have a text file that I am converting to binary. Its a 7 digit no. followed by a name and then repeat for however many names is listed.

1234567 First Last
7654321 First Last

Because its a 7 digit int, I am having trouble outputting it to the binary using this method with the int struct. It gives me an awfully large .DAT (binary) file whenever I write to it even with say just 3 names. Is there a better way of outputting it so my binary .dat files look about 200kb and doesn’t end up in the 20mb+ range?

const int MAX = 50;

struct StudentRegistration{
    int studentID;
    char name[MAX];
};

    fstream afile;
    ifstream infile;

  afile.open (fileName2, ios::out | ios::binary);
    infile.open (fileName1);

 while (infile >> s.studentID)
    {
        infile.get(space);
        infile.getline(&s.name, MAX);
        afile.seekp((s.studentID-1)*sizeof(StudentRegistration), ios::beg);
        afile.write(reinterpret_cast <const char *>(&s), sizeof(s));
    }

    afile.close();
    infile.close();

Answer 1

I removed the seekp line and it seems to do what I want to it for now.