Question

I have a text file which has data as follows:

Surrender~abc~nov@2012
Surrender~bnc~bhdgvx
Surrender~nkhjb~bcdjh
.
.
.

I want to separate the data row by row and store second and third column values in Hashmap as 2nd -> key and 3rd -> value and check if the value entered by user exist in the Hashmap and return true.

I tried following but getting java.lang.ArrayIndexOutOfBoundsException: 3..Please guide.

HashMap hm = new HashMap();
FileInputStream fstream = new FileInputStream("Surrender.txt");
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));

String strLine;
while ((strLine = br.readLine()) != null)   {
    String[] parts = strLine.split("~");
    for (int i = 0; i <= parts.length; i++) {
       if(!parts[i].equalsIgnoreCase("Surrender")){
    String key=parts[i];
    String value=parts[i++];
    if(key!=null && value!=null)
    hm.put(key,value);
}
    }
}

System.out.println("HashMap size..." + hm.size());
in.close();

Answer 1

Since each of your lines looks like this:

Surrender~abc~nov@2012

there are three parts after splitting by ~:

• Surrender
• abc
• nov@2012

These parts are numberd from 0 to 2.

Solution: Don’t loop over the parts. Do this instead:

hm.put(parts[1], parts[2]);

Drop these lines:

for (int i=0;i<=parts.length;i++) {
    if (!parts[i].equalsIgnoreCase("Surrender")) {
        hm.put(parts[i], parts[++i]);
    }
}

Note: Use a generic Map:

Map<String, String> hm = new HashMap<>(); // Java 7