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Home/ Questions/Q 8927577
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T08:14:57+00:00 2026-06-15T08:14:57+00:00

I have a the following code that i intend to should return a filepath

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I have a the following code that i intend to should return a filepath name from mysql in the php section and then display the image in html. But i am only getting up a tiny thumbnail in my browser. By the way “username” and “imagefile” are the only columns in the table “images”.

I’m sure there is just some silly mistake but i need a fresh pair of eyes to spot it. Thanks a lot in advance. P.S i know i should really me moving over to mysqli but i will simply translate at a later date. Cheers

<?php


session_start();
$username = $_SESSION['username'];

$con = mysql_connect('localhost','root','password');
mysql_select_db("db");


$profileimage = mysql_query("

SELECT * FROM images WHERE username='$username'

");

$row = mysql_fetch_array($profileimage);
$showimage = $row['imagefile'];

?>

<html>

<img src = "$showimage">


</html>
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  1. Editorial Team
    Editorial Team
    2026-06-15T08:14:58+00:00Added an answer on June 15, 2026 at 8:14 am

    First off, HTML doesn’t know what "$showimage" means. That is a PHP variable and HTML cannot interpret it. You need to output it so that HTML can just deal with the result.

    So if the value for $showimage is "/images/foo.jpg" you would need something like:

    <img src="<?php echo $showimage; ?>" />
    

    which would give you

    <img src="/images/foo.jpg" />
    

    Now, switching things to mysqli is as simple as replacing mysql with mysqli. It’s no more complicated than that. Since it looks like you are just starting to learn about these things you may as well, when you go to improve things, learn about PDO.

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