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Home/ Questions/Q 6999783
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T20:35:11+00:00 2026-05-27T20:35:11+00:00

I have a thread called mainloop i.e. int run_mainloop; void* mainloop(void* param) { //

  • 0

I have a thread called mainloop

i.e.

int run_mainloop;

void* mainloop(void* param)
{
    // local vars
    // initialize local vars

    while(run_mainloop)
    {
       // run mainloop
    }

    return 0;
}

The thread is kicked off from a function called client_open, i.e.

int client_open()
{
    run_mainloop = 1;
    return pthread_create(&thread, NULL, mainloop, NULL);     
}

However, in mainloop if initializing local variables fails I need to inform client_open right away of early exit.

pthread_join is inappropriate as it will block and I can’t have client_open block.
If it was to wait a short time before returning that would be ok.

How could I do this in a nice way without using pthread_join which will block.
I want to be able to get the return code.

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  1. Editorial Team
    Editorial Team
    2026-05-27T20:35:12+00:00Added an answer on May 27, 2026 at 8:35 pm

    Using pthread_tryjoin_np would be incorrect: the new thread could be arbitrarily delayed between pthread_create return, and the new thread actually executing initialization code.

    If you pthread_tryjoin_np during that delay, the join will fail and you will decide that everything is “a-ok”, when in fact it isn’t.

    What you want is a condition: client_open will await on it, and the mainloop will signal it (upon being done with initialization).

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