Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7895621
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 3, 20262026-06-03T07:41:15+00:00 2026-06-03T07:41:15+00:00

I have a tooltip with data loaded from ajax: $(‘.show_tooltip’).hover( function(){ $.post(‘getdata.php’, function(data) {

  • 0

I have a tooltip with data loaded from ajax:

$('.show_tooltip').hover(
    function(){
        $.post('getdata.php', function(data)    {
            $('#tooltip').html(data);
            $('#tooltip').show()
        });
    },
    function(){
        $('#tooltip').hide(); 
    }
);

It works.
But the problem is – when I hover it over element and quickly move mouse out, so $('#tooltip').show() have no effect, and it hide(). But then when data is loaded it popsup and stays shown without any hover.

What can be done about that. Is there any way to stop post request altogether?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-03T07:41:16+00:00Added an answer on June 3, 2026 at 7:41 am

    The jQuery AJAX methods return a jqXHR object which is an extension of the native XMLHttpRequest object, which has an abort method to stop the request:

    var xhr;
    $('.show_tooltip').hover(
        function(){
            //Save reference to the jqXHR object
            xhr = $.post('getdata.php', function(data) {
                $('#tooltip').html(data);
                $('#tooltip').show()
            });
        },
        function(){
            xhr.abort(); //Abort the request
            $('#tooltip').hide(); 
        }
    );
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a tooltip being used on hover from a tr. I am using
I have a simple html multiline tooltip implementation: this.tooltip = function(tag) { xOffset =
I have a notification system that works with the following codes jQuery: $(document).ready(function(){$.get('/codes/php/nf.php', function(data)
I have a tooltip on an anchor element, that sends an AJAX request on
I have written a function that positions a tooltip just above a textbox. The
I have an html page full of data. Whenever the user hovers over an
While working with jQuery and PHP a problem occurs with loading new data from
I have a JTable where I display some string data formatted using html. I
I have a global javascript function which .appends() a tooltip element to any element
If I have this code: foreach (QListWidgetItem *ii, selectedItems()) { urls.push_back(ii->data(Qt::ToolTip).toString()); } Would selectedItems()

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.