Question

I have a tricky XSL problem at the moment.
I need to copy the existing XML, copy a certain element (plus its child elements) and modify the value of two child-elements.
The modifications are: divide value of the ‘value’ element by 110 and edit the value of the ‘type’ element from ‘normal’ to ‘discount’.

This is currently what I have:

Current XML:

<dataset>
  <data>
   <prices>
    <price>
      <value>50.00</value>
      <type>normal</type>
    </price>
  </prices>
 </data>
</dataset>

Expected result

<dataset>
  <data>
   <prices>
    <price>
      <value>50.00</value>
      <type>normal</type>
    </price>
    <price>
      <value>45.00</value>
      <type>discount</type>
    </price>
  </prices>
 </data>
</dataset>

Any takers?
I’ve gotten as far as copying the desired ‘price’ element using copy-of, but I’m stuck as to how to modify it next.

Answer 1

Your spec is a little off — your value is the result of multiplying by .9, not dividing by 110. The below assumes you want to edit everything with a “normal” price — change the template match pattern for your particular node or set of nodes.

<xsl:stylesheet version="1.0" 
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="xml"/>

  <xsl:template match="/dataset/data/prices/price[type='normal']">
    <xsl:apply-templates/>
    <xsl:copy>
      <value><xsl:value-of select="format-number(value * 0.9, '0.00')"/></value>
      <type>discount</type>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>