Question

I have a type called MyType that is an int:

typedef int MyType;

It gets treated as an int throughout the code.

I’d like to be able to overload an operator separately for both int and MyType:

class C
{
public:
   C& operator>>(int i) {}
   C& operator>>(MyType i) {}
};

but I can’t:

overload.cpp:7:7: error: 'C& C::operator>>(MyType)' cannot be overloaded
overload.cpp:6:7: error: with 'C& C::operator>>(int)'

Can I have my cake and eat it too?

Answer 1

As per usual, you need a strong typedef. One implementation of that is BOOST_STRONG_TYPEDEF.