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Home/ Questions/Q 8402873
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T22:11:18+00:00 2026-06-09T22:11:18+00:00

I have a type Type and a variable tmp : template<typename Type> myFunction() {

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I have a type Type and a variable tmp :

template<typename Type> myFunction()
{
    /* SOMETHING */ tmp = 0;
};

I would like to declare tmp as Type if Type is a floating-point type and as double if Type is an integral type. How to do that in C++11 ?

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  1. Editorial Team
    Editorial Team
    2026-06-09T22:11:20+00:00Added an answer on June 9, 2026 at 10:11 pm
    typedef typename std::conditional<
         std::is_floating_point<T>::value, 
         T,                                //if floating, ::type = T
         double                            //else,        ::type = double
    >::type value_type;
    
    value_type tmp; //declare variable
    

    I’m assuming T can be only arithmetic type. If you want, you can use std::is_arithmetic to check that first. See other helpful type traits here:

    • Type traits
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