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Home/ Questions/Q 5996723
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:09:57+00:00 2026-05-23T00:09:57+00:00

I have a ui coded ui test in visual studio 2010. I want to

  • 0

I have a ui coded ui test in visual studio 2010.
I want to write a code which will:

  1. Discover all the controls on a window and child windows which are button, grid, label
  2. write a uimap with the id which is the name of the control in the code.

For starting it, I’ve write the following:

public void CodedUITestMethod1()
{    
   string uiTestFileName = @"D:\dev11\ConsoleApplication1\TestProject1\UIMap.uitest";

   UITest uiTest = UITest.Create(uiTestFileName);

   Microsoft.VisualStudio.TestTools.UITest.Common.UIMap.UIMap newMap = new Microsoft.VisualStudio.TestTools.UITest.Common.UIMap.UIMap(); 
   newMap.Id = "UIMap"; 
   uiTest.Maps.Add(newMap);

   GetAllChildren(BrowserWindow.Launch(new Uri("http://bing.com")), uiTest.Maps[0];);
   uiTest.Save(uiTestFileName);    
}

private void GetAllChildren(UITestControl uiTestControl, Microsoft.VisualStudio.TestTools.UITest.Common.UIMap.UIMap map)
{
   foreach (UITestControl child in uiTestControl.GetChildren())
   {
       map.AddUIObject((IUITechnologyElement)child.GetProperty(UITestControl.PropertyNames.UITechnologyElement));

       GetAllChildren(child, map);    
    }    
}

But it insert into the recursive loop and doesn’t end it.

Can anyone help me?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:09:58+00:00Added an answer on May 23, 2026 at 12:09 am

    I think that to avoid possible infinite recursion you have to add this code:

    private void GetAllChildren(UITestControl uiTestControl, Microsoft.VisualStudio.TestTools.UITest.Common.UIMap.UIMap map)
    {
      foreach (UITestControl child in uiTestControl.GetChildren())
      {
          IUITechnologyElement tElem=(IUITechnologyElement)child.GetProperty(UITestControl.PropertyNames.UITechnologyElement);
          if (!map.Contains(tElem))
          {
              map.AddUIObject(tElem);
              GetAllChildren(child, map);    
          }
      }    
    }
    

    This way you avoid to consider the same object multiple times and keep away from possible visual tree cycle.

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