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Home/ Questions/Q 6682385
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:41:59+00:00 2026-05-26T04:41:59+00:00

I have a UIView class which I add to my main UIViewController and I

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I have a UIView class which I add to my main UIViewController and I need to check the orientation of the device (iPad) at the launch of the app, in the viewDidLoad method. However because the class is a UIView (not UIViewController) I can’t use methods such as willAnimateRotationToInterfaceOrientation.

So I attempted to use this in my UIView class:

if (([[UIDevice currentDevice] orientation] == UIDeviceOrientationLandscapeLeft) ||
    ([[UIDevice currentDevice] orientation] == UIDeviceOrientationLandscapeRight)) {

However, testing with some breakpoints, whatever the orientation is, the of statement is never called, its skips right passed it. So what do you suggest I do to overcome this issue?

I need to somehow detect the orientation from the UIView class.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:42:00+00:00Added an answer on May 26, 2026 at 4:42 am

    Where are you placing the check? The location could easily explain why it’s not being called. To get rotation info, you could register for a notification, or have your view controller call a method in your view. Sample code for the latter:

    // ViewController.m
    - (void)willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation duration:(NSTimeInterval)duration {
        [self.customView willRotateToOrientation:toInterfaceOrientation];
    }
    
    // CustomView.m
    - (void)willRotateToOrientation:(UIInterfaceOrientation)newOrientation {
        // Handle rotation
    }
    

    The view controller method is one you override; the view’s method should be declared in a header.

    Update:
    Alternatively, you can find out the rotation in the controller’s `viewWillAppear’:

    // ViewController.m
    - (void)viewWillAppear {
        [self.customView willRotateToOrientation:[[UIDevice currentDevice] orientation];
    }
    

    The method in your view will be called accordingly.

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