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Home/ Questions/Q 7047975
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:50:09+00:00 2026-05-28T02:50:09+00:00

I have a UIViewController that should lazily load a view and then keep it

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I have a UIViewController that should lazily load a view and then keep it in memory as it’s re-used quite often until e.g. a memory warning occurs or I want to clean it for some other reason. In order to achieve the lazy loading, I’ve overwritten the default getter. Here’s my code:

@interface MyController {
    MyView *_myView;
}
@property(nonatomic, retain) MyView *myView;
@end

@implementation MyController
@synthesize myView = _myView;
- (MyView *)myView {
    if(_myView == nil) {
        _myView = [[MyView alloc] init];
        // some more initialization
    }
    return _myView;
}

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // the main part of my interest, freeing myView again
    self.myView = nil;
}
@end

Now my question is basically: Is it still correct to release myView like I did in - (void)didReceiveMemoryWarning or would I have to [_myView release]; _myView = nil; or even something completely different?

Also, is this generally the correct way of using lazy initialization or should I improve something here in general?

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:50:10+00:00Added an answer on May 28, 2026 at 2:50 am

    Your statement for releasing the memory is absolutely correct and there is no difference between two.

    self.myView = nil;
    

    In this case the setter method for myView property will be called and similar to as below.

    -(void) setMyView:(MyView*) aMyView {
       [myView release];
       myView = aMyView;
    }
    

    for the lazy loading … I guess -(void)viewDidDisappear for releasing the views and others memory related stuff and -(void) loadview to recreate them again

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