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Home/ Questions/Q 749447
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:26:09+00:00 2026-05-14T14:26:09+00:00

I have a User class that hasMany = [friends:User] Now I am trying to

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I have a User class that hasMany = [friends:User]

Now I am trying to display the friends list – ${user.friends}

However, I’d like to be able to apply parameters like I can with, for example, User.findAllBy(user, [max:10, sort: ‘dateCreated’, order: ‘desc”])

Can someone kindly tell me how to do this on a one-to-many in Grails / Groovy ?

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:26:09+00:00Added an answer on May 14, 2026 at 2:26 pm

    I’d use HQL:

    String hql = '''
    select u from User u, User u2
    where u in elements(u2.friends) and u2=:user
    order by u.dateCreated desc
    '''
    int max = ...
    int offset = ...
    def friends = User.executeQuery(hql, [user: user], [max: max, offset: offset])
    

    You could try to filter the friends collection, but as soon as you do anything with it it’ll get fully loaded from the database, so if you only want 10 instances you’ll have wasted loading all of the rest.

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