Question

I have a user level field in my database that contains either 1 or 2. what I want to do is to get the row that has the username that I inputted that contains level 2. Here is my code:

<?php

    $con=mysql_connect("localhost","root","");
    mysql_select_db("nnx",$con);

    $tbl=mysql_query("SELECT * FROM order");
    while($row=mysql_fetch_array($tbl))
    {

       if (($row['level']=='2')&&($row['username']==$_POST['user']))
       {
            echo $row['username']."".$row['garlique']."".$row['rightcee'];
        echo $row['oleia']."<br />";
       }
       else
       {
        echo $row['username']."".$row['garlique']."".$row['rightcee'];
        echo .$row['oleia']."<br />";
       }
        }
?>

When I tried to test it, an error "unexpected $end" showed. What I think is wrong in my code is the validation if.. ($row['level']=='2').. I don’t have any idea how to fix this kind of problem. I am a beginner in php, so if you could help me out, I would appreciate it very much. 🙂

Answer 1

Close your while loop with }. Syntax error.